Well, the closer you are to the North Pole, the easier time you will have crossing time zones, distance-wise.
Since I’m doing the math on my phone, I’m using an approximation of the Earth being a sphere with a radius of 6371km, and your train track is directly west, all at the same latitude, and equal longitude based timezones every 15°.
The circle around our Earth at that latitude has a circumference of 2 × pi × 6371 × cos(theta), kilometres, where theta is the latitude (imagine a triangle between the starting location, the centre of our model Earth and a point partway along a line that connects the equator and the centre). Divide that by 24, and that is the distance you need to travel in my model scenario to go back an hour, and thus the speed in km/h the westbound train needs to go to repeat the same hour again consistently.
Examples:
- Going directly west from Vladivostok: 1667.92 × cos (43.12°) = 1217 km/h
- Going to St. Petersburg: 1667.92 × cos(59.94°) = 835 km/h
- Going from the tip of the mainland of the Russian Far East: 1667.92 × cos(66.06°) = 677km/h
- To Murmansk: 1667.92 × cos(68.98) = 598 km/h
- From Saskylaky, a rural settlement: 1667.92 × cos(71.96°) = 516 km/h
- From the uninhabited top of the Russian mainland through a railway on the ocean: 1667.92 × cos(77.74°) = 354 km/h
- From Rudolf Island, northernmost island in Russia: 1667.92 × cos(81.76°) = 239 km/h










Was Lenovo one of the companies who signed 4 year profit gravy train contracts with one of the big 3, return of the RAM cartel? This kind of statement might suggest they did.